4x^2-4x+10=2x^2+5x-8

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Solution for 4x^2-4x+10=2x^2+5x-8 equation: 



4x^2-4x+10=2x^2+5x-8

We move all terms to the left:

4x^2-4x+10-(2x^2+5x-8)=0

We get rid of parentheses

4x^2-2x^2-4x-5x+8+10=0

We add all the numbers together, and all the variables

2x^2-9x+18=0

a = 2; b = -9; c = +18;
Δ = b2-4ac
Δ = -92-4·2·18
Δ = -63
Delta is less than zero, so there is no solution for the equation

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